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Series....

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1 Series.... on Wed Apr 07, 2010 5:46 am

Lucifer


Admin
Given the following series 2, 4, 6, 8, ......., 198, 200
The below defined operation is carried out on the above set of nos. for 99 times...
Operation : Take any 2 nos. at random and replace them by a single no. such that the replaced no. is one less than the sum of the 2 selected nos.

What is the number that would be left at the end ?

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2 Re: Series.... on Fri Apr 09, 2010 3:27 am

Its nothing but summing up the numbers and subtracting one 99 times
(100/2)(2+200) - 1*99 = 50(202) - 99 = 50(202-2) +1 = 50(200) - 1 = 10000-1 = 9999

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3 @indranil.. on Fri Apr 09, 2010 3:31 am

Lucifer


Admin
calculation mistake.... Very Happy

50(202-2) +1 = 50(200) + 1 = 10000+1 = 10001

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4 Re: Series.... on Fri Apr 09, 2010 4:07 am

Razz yaar ... poori zindagi bhar silly mistake karta raha ... saala abhi bhi nahi sudhra Smile ... socha tha + 1, likha -1

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